Chemistry Class 9 Chapter 1 Think-Thank, Federal board
Think-Thank
Chapter 1
Fundamentals of chemistry
1. What mass of sodium metal contains same number of atoms as 12.00 g of
carbon.
Ans.
12.00g of carbon = 1 mole
of carbon
No. of atoms in 1 mole of
C = NA = 6.022 x 1023
1 mole of Na = 23 g
So, no. of atoms in 1 mole
of Na = NA = 6.022 x 1023
Hence, 23g of Na contains
same number of atoms as 12g of C.
2. What mass of oxygen contains same number of molecules as 42g of
nitrogen.
Ans.
Molar mass of N2
= 2 x 14 = 28g
28g of N2 = 1
mole
1g of N2 = 1 /
28 mole
42g of N2 =
(1/28) x 42
= 1.5 mole
No. of molecules = 1.5 x
6.022 x 1023
= 9.03 x 1023
molecules.
So, mass of 9.03 x 1023
molecules of oxygen:-
Molar mass of O2 = 2 x 16 =
32g
Mass in grams = (No. of
molecules x Molar mass) / NA
= (
9.03 x 1023 x 32 ) / 6.022 x 1023
=
47.98g = 48g
Hence, 48g of oxygen has same no.
of molecules as 42g of nitrogen.
3.
Calculate
mass of one hydrogen atom in grams.
Ans.
1 mole
of hydrogen = 6.022 x 1023 atoms
6.022 x
1023 atoms of hydrogen = 1.008g
1 atom
of hydrogen = (1.008 / 6.022 x 1023)g
= 0.167 x
10-23g
= 1.67 x 10-24g
Hence,
1 atom of hydrogen is of 1.67 x 10-24grams.
4.
Observe
the given figure. It shows particles in a sample of air.
a)
Count
substances shown in the sample
There are five substances in the given
sample.
b)
Is
air a mixture or pure substance? Explain ?
Air is a homogenous mixture of various
gases. Each gas does not do reaction but retain its identity.
c)
Identify
the formula of each substance in air.
Nitrogen = N2
Oxygen = O2
Carbon dioxide = CO2
Water vapours = H2O
Argon = Ar
d)
Argue
whether each substance in air is an element or a compound.
N2 , O2 and Ar are
elements.
CO2 and H2O are
compounds.
e)
What
is the more common substance in air?
The most common substance in air is
nitrogen. 78% of air is N2.
5.
Calculate
the number of hydrogen atoms present in 18g of H2O.
Ans.
18g of H2O = 1 mole of H2O
1 mole of H2O = 6.022 x 1023
molecules
1 molecule of H2O = 2-H atoms
6.022 x 1023 molecules of H2O
= 2 x 6.022 x 1023 H-atoms
= 12.44 x 1023 atoms
= 1.24 x 1023 atoms
Hence, 18g of H2O has 1.24 x 1023
atoms of H.
6.
Calculate
total number of atoms present in 18g of H2O.
Ans.
Total no. of atoms in 1 molecule of H2O
= 3 atoms ( 2-H , 1-O)
18g of H2O = 1 mole = 6.022 x 1023
molecules
6.022x 1023 molecules of H2O
= 3 x 6.022 x 1023
=
18.06 x 1023 atoms
=
1.806 x 1024 atoms.
Hence, 18g of H2O
has total 1.806 x 1024 atoms.
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