Chemistry Class 9 Chapter 1 Think-Thank, Federal board

 

Think-Thank

Chapter 1

Fundamentals of chemistry

 

 

1.       What mass of sodium metal contains same number of atoms as 12.00 g of carbon.

Ans.

12.00g of carbon = 1 mole of carbon

No. of atoms in 1 mole of C = NA = 6.022 x 1023

1 mole of Na = 23 g

So, no. of atoms in 1 mole of Na = NA = 6.022 x 1023

Hence, 23g of Na contains same number of atoms as 12g of C.

 

2.       What mass of oxygen contains same number of molecules as 42g of nitrogen.

Ans.

Molar mass of N2 = 2 x 14 = 28g

28g of N2 = 1 mole

1g of N2 = 1 / 28 mole

42g of N2 = (1/28) x 42

                 = 1.5 mole

No. of molecules = 1.5 x 6.022 x 1023

                               = 9.03 x 1023 molecules.

So, mass of 9.03 x 1023 molecules of oxygen:-               

Molar mass of O2 = 2 x 16 = 32g

                 Mass in grams = (No. of molecules x Molar mass) / NA

                                            = ( 9.03 x 1023 x 32 ) / 6.022 x 1023

                                            = 47.98g = 48g

              Hence, 48g of oxygen has same no. of molecules as 42g of nitrogen.

3.       Calculate mass of one hydrogen atom in grams.

Ans.

1 mole of hydrogen = 6.022 x 1023 atoms

6.022 x 1023 atoms of hydrogen = 1.008g

1 atom of hydrogen = (1.008 / 6.022 x 1023)g

                                    = 0.167 x 10-23g

                                   = 1.67 x 10-24g

Hence, 1 atom of hydrogen is of 1.67 x 10-24grams.

4.       Observe the given figure. It shows particles in a sample of air.

a)       Count substances shown in the sample

There are five substances in the given sample.

b)       Is air a mixture or pure substance? Explain ?

Air is a homogenous mixture of various gases. Each gas does not do reaction but retain its identity.

c)        Identify the formula of each substance in air.

Nitrogen = N2

Oxygen = O2

Carbon dioxide = CO2

Water vapours = H2O

Argon = Ar

d)       Argue whether each substance in air is an element or a compound.

N2 , O2 and Ar are elements.

CO2 and H2O are compounds.

e)       What is the more common substance in air?

The most common substance in air is nitrogen. 78% of air is N2.

5.       Calculate the number of hydrogen atoms present in 18g of H2O.

Ans.

18g of H2O = 1 mole of H2O

1 mole of H2O = 6.022 x 1023 molecules

1 molecule of H2O = 2-H atoms

6.022 x 1023 molecules of H2O = 2 x 6.022 x 1023 H-atoms

                                                      = 12.44 x 1023 atoms

                                                      = 1.24 x 1023 atoms

Hence, 18g of H2O has 1.24 x 1023 atoms of H.

6.       Calculate total number of atoms present in 18g of H2O.

Ans.

Total no. of atoms in 1 molecule of H2O = 3 atoms ( 2-H , 1-O)

18g of H2O = 1 mole = 6.022 x 1023 molecules

6.022x 1023 molecules of H2O = 3 x 6.022 x 1023

                                          = 18.06 x 1023 atoms

                                          = 1.806 x 1024 atoms.

                 Hence, 18g of H2O has total 1.806 x 1024 atoms.

 

 

 

 

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